If p is the probability of not doing multiplication:<BR>2p + 5 (1 - p) <= 3<BR>2p - 5p <= 3 - 5<BR>-3p <= -2<BR>p >= 2/3<BR><BR>So, if multiplication takes 3 cycles then saving 2/3 of them will give a ...
I'm getting ready to start working on a C/C++ project that will be building and solving large tri-diagonal, block tri-diagonal and triangular matrices. I know there are a lot of libraries available ...
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